6y^2+36y+0=0

Solution for 6y^2+36y+0=0 equation:

6y^2+36y+0=0

We add all the numbers together, and all the variables

6y^2+36y=0

a = 6; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·6·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*6}=\frac{-72}{12}
=-6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*6}=\frac{0}{12}
=0
$